X^2-17x+17=0

Solution for X^2-17x+17=0 equation:

X^2-17X+17=0

a = 1; b = -17; c = +17;
Δ = b2-4ac
Δ = -172-4·1·17
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{221}}{2*1}=\frac{17-\sqrt{221}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{221}}{2*1}=\frac{17+\sqrt{221}}{2}
$